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tan70°COS10°

作者:admin 更新时间:2025-07-31
摘要:tan70×cos10×(√3tan20-1) =tan70×cos10×(tan60×tan20-1) =tan70×cos10×[(sin60×sin20/cos60×cos20)-1] =tan70×cos10×(sin60×sin20-cos60×cos20)/(cos60×cos20) =tan70×cos10×[-cos(60+20)]/(cos60 ×cos20) =-tan70×cos10×cos80/(cos60×,tan70°COS10°

 

tan70×cos10×(√3tan20-1)

=tan70×cos10×(tan60×tan20-1)

=tan70×cos10×[(sin60×sin20/cos60×cos20)-1]

=tan70×cos10×(sin60×sin20-cos60×cos20)/(cos60×cos20)

=tan70×cos10×[-cos(60+20)]/(cos60 ×cos20)

=-tan70×cos10×cos80/(cos60×cos20)

=-tan70×cos10×sin10/(cos60×cos20)

=-(sin70/cos70)×(1/2)×sin20/(cos60×cos20)

=-(cos20/sin20)×sin20/(2cos60×cos20)

=-1/(2cos60)

=-1